/* UVa 10169, Accepted, 0.140s, 2009-05-27 18:25:56 (UTC) */

#include<stdio.h>

#define N 1000001
double p1[N], p2[N];

int main(){
  int i,n;
  double p, lg10=log(10);

  p1[0]=1; p2[0]=0;
  for(i=1;i<N;i++){
    p=1.0/i/(i+1);
    p1[i]=p1[i-1]*(1-p);
    p2[i]=p2[i-1]+log(p);
  }

  while(scanf("%d",&n)==1) printf("%.6lf %d\n",1-p1[n],(int)(-p2[n]/lg10));

  return 0;
}